contoh soal suku banyak

1. EBTANAS 1990 Suku banyak f(x) jika dibagi (x – 2) sisanya 24 dan dibagi (x + 5) sisana 10. Apabila f(x) tersebut dibagi x2 + 3x – 10 sisanya adalah… a. x + 34 c. x +10 b. x – 34 d. 2x + 20 e. 2x – 20 Penyelesaian: f(x) = g(x) (x – 2) + 24 f(2) = 24 f(x) = g(x) (x + 5) +10 f(- 5) = 10 f(x) = g(x) (x2 + 3x – 10) + Ax + B f(X) = g(x) (x + 5) (x – 2) + Ax + B f(- 5) = 0 – 5A + B = 10 f(2) = 0 + 2A + B = 24 - -7A = - 14 A = 2 - 5A + B = 10 B = 10 + 5A B = 10 + 5. 2 B = 10 + 10 B = 20 Maka sisanya : Ax + B = 2x +20